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The radius of gyration of a solid shapere of radius r about a certain axis is r. The distance of this axis from the centre of the shpere isA. rB. 0.5rC. `sqrt(0.6) r `D. `sqrt(0.4)r` |
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Answer» Correct Answer - 3 `2/5 mr^(2)+mx^(2)=mr^(2)` `rArr x=sqrt(0.6)r` |
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