1.

The radius of gyration of a solid sphere of radius about a certain axis is r. The distance of that axis from the centre of the sphere is

Answer»

`(2)/(5)r`
`sqrt((2)/(5))r`
`sqrt(0.6)r`
`sqrt((5)/(3))r`

Solution :From parallel AXIS theorem `I=I_(C)+Md^(2)`
`:. mr^(2)=(2)/(5)mr^(2)+Md^(2)`
`d= sqrt((3)/(5))r= sqrt(0.6)r`


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