1.

The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass is

Answer»

`(L)/(SQRT(12))`
`(L^2)/(sqrt(12))`
`(L)/(sqrt3)`
`(L)/(SQRT2)`

Solution :`I = Mk^(2) = (ML^(2))/(12) THEREFORE K = (L)/(sqrt(12))`


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