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The radius of hydrogen atom in its ground state is `5.3 xx 10^-11 m`. After collision with an electron it is found to have a radius of `21.2 xx 10^-11 m`. The principal quantum number of the final state of the atom is.A. n=4B. n=2C. n=16D. n=3 |
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Answer» Correct Answer - B `rpropn^(2)i.e.,(""^rf)/(r_(i))=((n_(f))/(n_(i)))^(2)` `rArr " " (21.2xx2xx10^(-11))/(5.3xx10^(-11))=((n)/(1))^(2)rArrn^(2)=4rArrn=2` |
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