1.

The radius of La^(3+) (At No. of La = 57) is 1.06Å. Which one of the following given value will be closest to the radius fo Lu^(3+) (Atomcic NO. ofLu = 71) ?

Answer»

`1*40Å`
`1*06Å`
`0*85Å`
`1*60Å`

Solution :Due to lanthanoid contraction, the ionic RADII of LANTHANOIDS decreases from `La^(3+)` to `LU^(3+)`. Therefore, the lowest value (0.85 Å) is the ionic radius of `Lu^(3+)`


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