The radius of Na^(+) cation is less than that of Na atom. Give reason.

1.	The radius of Na^(+) cation is less than that of Na atom. Give reason.
Answer» Solution :For the formation of cation, their is loss of an electron which means its RADIUS decreases. Due to decrease in no. of electrons nuclear FORCES increases pet electrons. As a RESULT, radius of cation decrease as the effective nuclear charge increases. e.g., ionic radius of Nat is smaller than that of PARENT atom Na. `Na to Na^(+)+ 1e^(-)` `{:("Electrons",11,10),("Nuclear charge",11,11),("Ionic size",186 "pm", 95 "pm"):}` pm= PICO METER `=10^(-12) cm`

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