The radius of Na^(+) ion is 95 pm and that of Cl^(-) ion is 181 pm. Pr – InterviewSolution

1.	The radius of Na^(+) ion is 95 pm and that of Cl^(-) ion is 181 pm. Predict the structure of Na^(+)Cl^(-) and the coordination number of cation.
Answer» Solution :`(r_(Na^(+)))/(r_(CL^(-)))=(95)/(181)= 0.524` Since the RADIUS ratio lies between 0.414-0.732, the structure will be OCTAHEDRAL with coordination NUMBER 6.

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