The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edge length of unit cell in NaCl would be (pm).A. 181B. 95C. 276D. 552

The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edg

1.	The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edge length of unit cell in NaCl would be (pm).A. 181B. 95C. 276D. 552
Answer» Correct Answer - 4 Edge length =`2(r_(c)+r_(a))`

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The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edge length of unit cell in NaCl would be (pm).A. 181B. 95C. 276D. 552

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