The radius of one circular field is 20 m and that of another is 48 m.

1.	The radius of one circular field is 20 m and that of another is 48 m. find the radius of the third circular field whose area is equal to the sum of the areas of two fields.
Answer» Let A₁= the area of the circle whose radius is 20 m [given] A₂= the area of the circle whose radius is 48 m [given] Now we have to find the radius of third circle such that whose area is equal to the sum of areas of two fields. Hence, A₃= A₁ + A₂ ⇒ πr² = π(20)² + π(48)² ⇒ πr² = π[(20)² + (48)²] ⇒ r² = 400 + 2304 ⇒ r = 52 m Therefore radius = 52 m

The radius of one circular field is 20 m and that of another is 48 m. find the radius of the third circular field whose area is equal to the sum of the areas of two fields.

Answer»

Let A₁= the area of the circle whose radius is 20 m [given]

A₂= the area of the circle whose radius is 48 m [given]

Now we have to find the radius of third circle such that whose area is equal to the sum of areas of two fields.

Hence,

A₃= A₁ + A₂

⇒ πr² = π(20)² + π(48)²

⇒ πr² = π[(20)² + (48)²]

⇒ r² = 400 + 2304

⇒ r = 52 m

Therefore radius = 52 m