The radius of the circle 3x2 + by2 + 4bx – 6by + b2 = 0 is …(a) 1� – InterviewSolution

1.

The radius of the circle 3x2 + by2 + 4bx – 6by + b2 = 0 is …(a) 1 (b) 3(c) √10(d) √11

Answer»

(c) √10

Here b = 3

3x² + 3y² + 12x - 18y + 9 = 0

(÷ 3) zz > x² + y² + 4x – 6y + 3 = 0

Comparing with general form

g = 2, f = -3, c = 3

∴ radius = √(g² + f² - c) = √(4 + 9 - 3) = √10

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