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| 1. |
The radius of the circular conducting loop shown in is R. magnetic field is decreasing at a constant rate `alpha`. Resisitance per unit length of the loop is `rho`. Then, the current in wire `AB` is (`AB` is one of the diameters) A. `(R alpha)/(2 rho)` from A to BB. `(R alpha)/(2 rho)` from B to AC. `(2 R alpha)/(rho)` from A to BD. zero |
| Answer» Correct Answer - D | |