1.

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

Answer»


SOLUTION :`F=momega^2x,pixx(0.008)^2XX "X" xx1000 xx9.8= 24 xx10^(-3) xxomega^2 T , = 2pi//omega =2pi//82.058=0.076` second .


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