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The radius of the first electron orbit of a hydrogen atom is `5.3 xx 10^(-11)m`. What is the radius of the second orbit ? |
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Answer» `r_(n)prop n^(2)` `(r_(2))/(r_(1))=(2^(2))/(1^(2))=(4)/(1) rArr r_(2)=4r_(1)` `therefore r_(2)=4xx5.3xx10^(-11)=2.12xx10^(-10)m`. |
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