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The range of a projectile fired at an angle of `15^@` is 50 m. If it is fired with the same speed at an angle of `45^@` its range will beA. 25 mB. 37 mC. 50 mD. 100 m |
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Answer» Correct Answer - D `50=(V_(0)^(2)sin30^(@))/(g)` `R=(V_(0)^(2)sin90^(@))/(g)=100m` |
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