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The range of a projectile fired at an angle of `15^@` is 50 m. If it is fired with the same speed at an angle of `45^@` its range will beA. 60 mB. 71 mC. 100 mD. 141 m |
Answer» Correct Answer - C Horizontal range, `R = (u^(2) sin 2theta)/(g)` For the same speed. `R prop sin 2theta` `therefore (R_(1))/(R_(2)) = (sin2 xx15^(@))/(sin2 xx 45^(@)) = (sin 30^(@))/(sin 90^(@))` or `R_(2) = R_(1) (sin 90^(@))/(sin 30^(@)) = 50 m xx(1)/(((1)/(2))) = 100m` |
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