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The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be(a) 25 m (b) 37 m (c) 50 m (d) 100 |
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Answer» (d) 100 m. Explanation: In the first case Range = 50 = (u2 /g) Sin(2x15°) = (u2 /2g) => (u2 /g)=100 In the second case range = (u2 /g) Sin(2x45°) = (u2 /g) Sin90° =100 m |
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