InterviewSolution
Saved Bookmarks
| 1. |
The range of the function is `f(x)=log_5(25-x^2)` isA. `[0, 5]`B. ` [0, 2)`C. ` (0, 2)`D. none of these |
|
Answer» Correct Answer - D Cleary, f(x) is defined, if `25-x^(2) gt 0 rArr - 5 lt x lt 5` Now, let `y = log_(5) (25-x^(2))`. Then `5^(y) = 25- x^(2) rArr - 5 lt x lt 5` For x to real, we must have `25-5^(y) ge 0 rArr 5^(y) le 25 rArr y le 2` Also, `y =f(x) to - oo` as `x to pm5`. Hence, range `(f) = (-oo,2]` |
|