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The range of voltmeter of resistance `300 Omega` is 5 V. The resistance to be connected to convert it into an ammeter of range 5 A isA. ` 1 Omega "in series"`B. `1 Omega "in parallel"`C. `0.1 Omega "in series"`D. `0.1 Omega "in parallel"` |
Answer» Correct Answer - B A voltmeter is a galvanometer having a high resistance connected in series with it. The current through the galvanometer is `I_(g) = (5V)/(300 Omega) = 1/60 A` An ammeter is a galvanometer having a low resistance connected in parallel with it. The shunt resistance S is determined from `I_(g)/(I-I_(g)) = S/G` where `G=3000 Omega` (Given) For `I=5A`, we get `(1//60)/(5-(1//60)) = S/300 rArr S= 1Omega` |
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