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The range of water flowing out of a small hole made at a depth `10 m` below water surface in a large tank is `R`. Find the extra pressure (in atm) applied on the water surface so that range becomes `2R`. Take `1atm=10^(5)Pa`. |
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Answer» Correct Answer - 3 `V=(2gh)^(1//2)` Range will be twice, if efflux velocity becomes twice or h becomes four times or 40 m extra pressure`=` 30m of water head but 1 atm `=0.7xx13.6m` of water `=10.336m` of water, `30m` of water `=3.0atm`. |
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