The rank correlation coefficient between marks obtained by 10 students in English and Statistics was found to be 0.5. Find the sum of squares of different of ranks.

The rank correlation coefficient between marks obtained by 10 students

1.	The rank correlation coefficient between marks obtained by 10 students in English and Statistics was found to be 0.5. Find the sum of squares of different of ranks.
Answer» Solution :GIVEN : r=0.5,N=10 Now, `r=1-(6 sumD^(2))/(N^(3)-N)` `(6sumD^(2))/(N^(3)-N)=1-r` `(6sumD^(2))/(10^(3)-10)=1-0.5` `(6sumD^(2))/(1,000-10)=0.5` `(6sumD^(2))/(990)=0.5` `implies6sumD^(2)=0.5xx990` `implies 6sumD^(2)=495` `implies sumD^(2)=(495)/(6)` `impliessumD^(2)=82.5` Sum of SQUARES of Difference of Ranks=82.5.