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The rate constant at `25^(@)C` for the reaction of `NH_(4)^(+)` and `OH^(-)` to form `NH_(4)OH` is `4xx10^(10) M^(-1) sec^(-1)` and ionisation constant of aq. `NH_(3)` is `1.8xx10^(-5)`. The rate constant of proton transfer to `NH_(3)` isA. `1.8 xx 10^(-5)`B. `7.2 xx 10^(+5)`C. `3.6 xx 10^(5)`D. `4.2 xx 10^(-5)` |
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Answer» Correct Answer - 2 `NH_(4)^(+) + OH^(-) overset(K_(1))to NH_(4)OH, k_(1) = 4 xx 10^(10)` `NH_(3) + H_(2)O overset(k_(1))iffNH_(4)^(darr) + OH^(-)` `K_(eq)=(K_(f))/(K_(b))` `rArr 1.8 xx 10^(-5)=(K_(f))/(4 xx 10^(10))` `rArr K_(f) = 7.2 xx 10^(5)` |
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