1.

The rate constant for a first order reaction is 60s^(-1). How much time will it take to reduce the concentration of the reactant to 1//10th of its initial value ?

Answer»


SOLUTION :`t=(2.303)/(K)LOG""(a)/(a-x)=(2.303)/(60S^(-1))log""(a)/(a//10)=(2.303)/(60s^(-1))log10=0.0384s`


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