1.

The rate constant for a fist order reaction is k = 7xx10^(-4)s^(-1) .The time taken for the reactant to be reduced to 1/2 of the initial concentration is :

Answer»

990 s
1980s
445 s
2970 s

SOLUTION :(B) `t=(2.303)/(k)"log"(1a)/(1//4a)`
`=(2.303)/(7XX10^(-4))"log"4 `
`t=(2.303)/(7xx10^(-4))xx0.0602`
= 1980 s


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