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The rate constant for an isomerisation reaction, AtoB is 4.5xx10^(-3)" min"^(-1). If the initial concentration of A is 1 M, calculate the rate of reaction after 1 h. |
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Answer» Solution :Rate CONSTANT in `min^(-1)` shows that it is a REACTION of 1st order. Hence, `k=(2.303)/(t)log""([A]_(0))/([A])` or `4.5xx10^(-5)min^(-1)=(2.303)/(60" min")log""(1)/([A])" or "log[A]=-0.1172=1.8828" or "[A]=" Antilog "1.8828` `:.[A]=0.7635" mol L"^(-1).` This is the concentration after 1 h. Rate after `1 h=k[A]=4.5xx10^(-3)xx0.7635" mol L"^(-1)min^(-1)=3.44xx10^(-3)" mol L"^(-1)mil^(-14).` |
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