1.

The rate constant k , for the reaction N_(2)O_(5) to 2NO_(2) (g) + (1)/(2) O_(2)(g) correspond to concentration of N_(2)O_(5) initially and at time t .

Answer»

`[N_(2)O_(5)]_(t) [N_(2)O_(5)]_(0) + KT`
`[N_(2)O_(5)]_(0) = [N_(2)O_(5)]_(t) e^(kt)`
`log_(10) [N_(2)O_(5)]_(t) = log_(10)[N_(2)O_(5)]_(0) - kt`
ln `([N_(2)O_(5)]_(0))/([N_(2)O_(5)]_(t))= kt`

Solution :Rate constant = `2.3 xx 10^(-2) sec^(-1)`
It means it is a FIRST order reaction (because UNIT of rate constant is `sec^(-1)`)
For first order reaction k = `(1)/(t)` ln `(a)/(a-x)`
Kt = ln `(a)/(a-x)` = ln `([N_(2)O_(5)]_(0))/([N_(2)O_(5)]_(t))`.


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