1.

The rate constant (k') of one of the reaction is found to be double that of the rate constant (k") of another reaction. Then the relationship between the corresponding activation energies of the two reactionscan be represented as

Answer»

`(E_agt E_a )`
`(E_a LT E_a )`
`(E_a = E_a)`
none of these.

Solution :As `k= Ae^(-E_a//RT)` THEREFORE if k. GT k" than `E_a. lt E_a...`


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