1.

The rate constant (K') of one reaction is double of the rate constant (K") of another reaction. Then the relationship between the corresponding activation energies of the two reactions (E_(a)^(') "and" E_(a)^('')) will be

Answer»

`E_(a) GT E_(a)`
`E_(a) = E_(a)`
`E_(a) lt E_(a)`
`E_(a) = 4E_(a)`

Solution :As `K' gt K'' . E'_(a) lt E''_(a)` (GREATER the rate CONSTANT , less is the activation energy).


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