1.

The rate constant of a reaction is 2.5xx10^(-2)" L mol"^(-1)s^(-1). Calculate the initial rate with concentration 0.2" mol L"^(-1).

Answer»

Solution :From the units of rate constant,
order of the reaction is 2.
For a SECOND order reaction, rate = k `"[concentration]"^(2)`
Initial rate of the reaction `=2.5xx10^(-2)(0.2)^(2)=1xx10^(-3)" MOL L"^(-1)s^(-1)`


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