The rate constant of a reaction is 2xx10^(-3)min^(-1) at 300 K tempera – InterviewSolution

1.	The rate constant of a reaction is 2xx10^(-3)min^(-1) at 300 K temperature .By increase in temperature by 20K,its value becomes three time,then calculate the energy of activation of the reactuon .what will be its rate constant at 310 K temperature?
Answer» Solution :`E_(a)`=10480 cal,K(310 K)=`3.126xx10^(-3)MIN^(-1)`

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