1.

The rate constant of a reaction is given by k=2.1xx10^(10)C^(-(2700)/(2.303R) It means that

Answer»

LOG K vs `(1)/(T)` will be straight line with slope `=(-2700)/(2.303R)`
log k vs `(1)/(T)` will be straight line with intercept on log k axis `=log 2.1xx10^(10)`
the NUMBER of effective collisions are `2.1xx10^(10)cm^(-3)sec^(-1)`
half-life of the reaction increases with increase in temperature

Solution :(A) and (B) are correct, (C ) is wrong because frequency factorgives total number of collisions and not the effective collision `cm^(-3)sec^(-1)`, (D) is wrong because half-life of the reaction decreases with increase in temperature (as reaction BECOMES faster)


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