1.

The rate constant of a reaction is given byk=2.1xx10^10 exp(-2700//RT). It means that

Answer»

log k versus `1/T` will be a straight LINE with SLOPE `=(-2700)/(2.303R)`
log k versus `1/T` will be a straight line withintercepton axis = 10.32
When Tbecomes INFINITE , `k=2.1xx10^10`
k is independent of temperature

Solution :From Arrehenius equation `k=Ae^(-E_(a)//RT)`
Given, `k=2.1xx10^10xxe^(-2700//RT)`

INTERCEPT =log A - log `(2.1xx10^10)`
= 10.32


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