1.

The rate constant of a second order reaction, 2A toProducts, is 10^(-4)" lit mol"^(-1)" min"^(-1). The initial concentration of the reactant is 10^(-2)" mol lit"^(-1). What is the half-life (in min) ?

Answer»

10
1000
100
`10^(6)`

Solution :Half -life period of a second ORDER REACTION
`t_(1//2) = (1)/("Rate CONSTANT" XX "Initial CONC.") = (1)/(ka)`
`=(1)/(10^(-4) L mol^(-1) min^(-1) xx 10^(-2) mol L^(-1))`
` = 10^(6) min`


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