1.

The rate constant of the reaction at temperature 200 K is 10 times less than the rate constant at 400 K.What is the activation energy of the reaction ?

Answer»

`1842.4" R"`
`921.2" R"`
`460.6" R"`
`230.3" R"`

SOLUTION :At `T_1=200 K,` if `k_1=k,` then
at `T_2 = 400 K, k_2=20 k `
`log""(10k)/k=E_a/(2*303R)(400-200)/(400xx200)" or "E_a=921*2R`.


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