1.

The rate constantfor areactionat 500^(@) C " is" 1.6 xx 10^(3) M^(-1)s^(-1). Whatis thefrequencyfactorof thereactionif itsenergyof activationis 56 kJ mol^(-1)

Answer»


SOLUTION :Given : `k = 1.6xx 10^(3)M ^(-1) s^(-1), T = 273+ 500= 773K`
Energyof activation= `E_(a)= 56 kJ mol^(-1) =56000 J mol^(-1)`
Frequencyfactor = A= ?
ByArrheniusequation
`k= AXX e^(-E_(a) //RT) :. " In" k= " In" A-(E_(a))/(RT)`
`2.303 log_(10)k = 2.303log_(10)A - (E_(a))/(RT):. log_(10) k =log_(10)A - (E_(a))/(2.303 RT)`
`:. log_(10) A= log_(10) k + (E_(a))/(2.303 RT)`
`= log_(10)1.6 xx 10^(3) + (56000)/(2.303 xx 8.314 xx 773) = 3.204 + 3.784= 6.988`
`:. A = AL 6.988= 9.727 xx 10^(6) s^(-1)`


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