1.

The rate equation for the decomposition of N_(2)O_(5) in "CC"l_(4) is rate =K[N_(2)O_(4)] where K=6.3x10^(-4)s^(-1) at 320 K. what would be the initial rate of decompositioni of N_(2)O_(5) in a 1.10M solution of N_(2)O_(4)?

Answer»

`6.3xx10^(-5)` MOL `"LITRE"^(-1)s^(-1)`
`0.63xx10^(-6)` mol `"litre"^(-1)s^(-1)`
`6.3xx10^(-5)` mol `"litre"^(-1)s^(-1)`
`0.63xx10^(-4)` mol `"litre"^(-1)s^(-1)`

Solution :`r=K.[N_(2)O_(5)]=6.3xx10^(-4)xx(0.10)^(1)=6.3xx10^(-5)`
`1N_(2)O_(5)to2NO_(2)+1/2O_(2)`


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