1.

The rate expression for the reaction A_((g)) + B_((g)) rarr C_((g))" is rate" = k[A]^(2)[B]^(1//2). What changes in the initial concentrations of A and B will cause the rate of reaction to increase by a factor of eight?

Answer»

[A`]=[A] : [B`] = 2[B]
[A`]=2[A] : [B`] = 4[B]
[A`]=[A] : [B`] = 4[B]
[A`] = 4[A] : [B`] = [B]

SOLUTION : Given `r= k[A]^2[B]^(1//2)`
new RATE will be 8 times when [A]. = 2[A] and [B]. = 4[B]
now `r. = [2A]^(2)[48]^(1//2)` = 8[A][B]


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