The rate law expresses the relationship of the rate of a reaction to the rate constant and the concentration of the reactants raised to some powers for the general reaction. aA+bBtocC+dD Rate law takes the form r=k[A]^(x)[B]^(y) where x and y are number that must be determined experimentely k is the rate constant and [A] and [B] are concentration of A & B respectively. The varitation of concentration of 'A' with time in two experiments starting with two different initial concentration of 'A' is given by the following graph.The reaction is represented by A(aq)toB(aq) what is rate of reaction (M//min) when conc. of A in aqueous solution was 1.8 M:

The rate law expresses the relationship of the rate of a reaction to t

1.	The rate law expresses the relationship of the rate of a reaction to the rate constant and the concentration of the reactants raised to some powers for the general reaction. aA+bBtocC+dD Rate law takes the form r=k[A]^(x)[B]^(y) where x and y are number that must be determined experimentely k is the rate constant and [A] and [B] are concentration of A & B respectively. The varitation of concentration of 'A' with time in two experiments starting with two different initial concentration of 'A' is given by the following graph.The reaction is represented by A(aq)toB(aq) what is rate of reaction (M//min) when conc. of A in aqueous solution was 1.8 M:
Answer» 0.072 M `"MIN"^(-1)` 0.1296 M `"min"^(-1)` 0.036 M `"min"^(-1)` 1 M `"min"^(-1)` SOLUTION :`r_1=0.3/5 M min^(-1) IMPLIES r_2=0.2/5` `r_1/r_2=[A_1/A_2]^m implies 0.3/0.2=(1.5/1)^mimplies m=1 : " " 0.3/5=k(1.5),k=1/25` `r=1/25xx1.8=0.072 MMIN^(-1)`