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The rate law for a reaction of A,B and C has been found to be rate = k[A]^2[B][L]^(3//2) How would the rate of reaction Change when (i) Concentration of [L] is quadrupled (ii) Concentration of both [A] and [B] are doubled (iii) Concentration of [A] is halved (iv) Concentration of [A] isreduced to (1//3)and consideration of [L] is quadrupled . |
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Answer» SOLUTION :Rate `=k[A]^2[B][L]^(3//2)........(1) ` (i) when [L]=[4L] Rate `=k[A]^2[B][4L]^(3//2)` Rate = 8 `(k[A]^2[B][L]^(3//2))......(2)` Comparing (1) and (2) , rate is increased by 8 times. (ii) when [A] = [2A] and [B] = [2B] Rate = `k[2A]^2[2B][L]^(3//2)` Rate = `8(k[A]^2[B][L]^(3//2) )............(3)` Comparing (1) and (3) , rate is increased by 8 times . (iii) When `[A] = (([A])/(2))` Rate `k=(([A]]/2)[B][L]^(3//2)` Rate `=(1/4)(k[A]^2[B][L]^(3//2))...........(4)` Comparing (1) and (4) , rate is reduced to `1/4` times. (IV) when [A] `= (([A])/(3))` and [L]=[4L] Rate `=k[A/3]^2[B][4L]^(3//2)` Rate `=(8/9)(k[A]^2[L]^(3//2)).........(5)` comparing (1) and (5) , rate is reduced to 8/9 times . |
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