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| 1. |
The rate law for the reaction : Ester +H^(+)to"Acid"+"Alcohol is ": (dx)/(dt)=k["Ester"][H^(+)]^(0) What would be the effect on the rate if (i) concentration of the ester is doubled ? (ii) concentration of H^(+) is doubled ? |
| Answer» SOLUTION :(i) The rate of REACTION will be doubled. (II) No effect on rate. | |