1.

The rate law for the reaction RCL + NaOH(aq) rarr ROH + NaCl is given by Rate = k[RCl]. The rate of the reaction will be

Answer»

unaffected by increasing temperature of the reaction
doubled on doubling the concentration of `NaOH`
HALVED on REDUCING the concentration of `NaOH` to one HALF
halved on reducing the concentration of `RCL` to one half

Solution :`R_(1) = k[RCl]^(1)[NaOH]^(0)`
`R_(2) = k[0.5 RCl]^(1)[NaOH]`
`:. R_(2) = 0.5 R_(1)`


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