The rate law from a reaction between the substances A and B is given b – InterviewSolution

1.	The rate law from a reaction between the substances A and B is given by rate = k[A]^(n)[B]^(m) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as
Answer» (m + N) (n - m) `2^((n-m))` `1/(2^((m+n)))` ANSWER :C

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