1.

The rate law of a reaction is : Rate = k[A]^(2)[B] On doubling the concentration of both A and B the rate x will become :

Answer»

`4x^(2)`
8X
`x^(3)`
9x

Solution :(B) Let rate = `k [A]^(2) [B] =x `
rate `= k [2A]^(2) [2B] = 8 b[A]^(2) [B] =8x `


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