1.

The rate of a first order reaction has been found to be 2.45xx10^(-6) "mol L"^(-1) s^(-1) at concentration C_(1). The value of C_(1) is (rate constant = 3.5xx10^(-5)) :

Answer»

7.0 MOL `L^(-1)`
0.7 mol `L^(-1)`
0.07 mol `L^(-1)`
2.1 mol `L^(-1)`

Solution :(C ) Rate = K(C )
`2.45 xx10^(-6) = 3.5 xx10^(-5) xxC_(1)`
or `C_(1) = (2.45xx10^(-6))/(35xx10^(-5))= 0.07 "mol L"^(-1)`
or `([A])/([A]_(0))= 1.77`
`([A]_(0))/([A])= (1)/(1.77) = 56 .35 %`
`:. ` Extent of reaction
`= 100 - 56.3 = 43.75 %`


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