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The rate of a first order reaction is 0.04" mol L"^(-1)s^(-1) at 10 seconds and 0.03" mol L"^(-1)s^(-1) at 20 seconds after initiation of the reaction. The half-life period of the reaction is |
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Answer» `44.1" s"` `k = (2*303)/((2)-t_(1)) log""([A]_(1))/([A]_(2))` Also for first order reaction, rate `alpha` [A]. Hence `k=(2*303)/(t_(2)-t_(1))log""(("Rate")_(1))/(("Rate")_(2))` `=(2*303)/((20-10))log((0*04)/(0*03))=0*0287 s^(-1)` `t_(1//2)=(0*693)/(k)=(0*693)/(0*0287s^(-1))=24*14s` |
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