1.

The rate of a first order reaction is 1.5 xx 10^(-2) mol L^(-1) "min"^(-1) at 0.5 M concentration of the reactant . The half life of the reaction is

Answer»

8.73 min
7.53 min
0.383 min
23.1 min

Solution :Rate `((DX)/(dt))` = k.c, `1.5 xx 10^(-2) = k xx 0.5`
For FIRST order k = `(1.5 xx 10^(-2))/(0.5) = 3 xx 10^(-2) "MINUTE"^(-1)`
`t_(1//2) = (.693)/(k) = (.693)/(3 xx 10^(-2)) = 23.1` minute.


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