1.

The rate of a first order reaction is 1.8xx10^(-3) "mol L"^(-1) when the initial concentration is 0.3 mol L^(-1) . The rate constant in the units of second is :

Answer»

`1xx10^(-2) s^(-1)`
`1xx10^(-4) s^(-1)`
`6xx10^(-2) s^(-1)`
`6xx10^(2) s^(-1)`

Solution :[B] RATE = K( C)
`1.8 xx10^(-3) = k(0.3)`
or `k=(1.8xx10^(-3))/(0.3)`
`= 6xx10^(-3) min^(-1)`
`=(6xx10^(-3))/(60)=1xx10^(-4)s^(-1)`


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