1.

The rate of a first order reaction : R rarr P is 7.5xx10^(-4) molL^(-1) "s"^(-1) . The rate concentration of R is 0.5 mol L^(-1) . The rate constant is :

Answer»

`2.5xx10^(-5) s^(-1)`
`1.5xx10^(-3)s^(-1)`
`4.16xx10^(-7) s^(-1)`
`1.50xx10^(5)s^(-1)`

Solution :(A) Rate `=7.5xx10^(-4) "mol L"^(-1) "MIN"^(-1)`
`(7.5xx10^(-4))/(60) mol L^(-1) s^(-1)`
Rate = k[R]
k = `("Rate")/([R])`
`= (7.4xx10^(-4))/(60xx0.5)`
`= 2.5 xx10^(-5)`


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