1.

The rate of a gaseous reaction is given by k[A] [B]. If the volume occupied by the reacting gases is suddenly reduced to half the original volume, the rate of the reaction relation relative to the initial rate will be

Answer»

`1//8`
`1//4`
`8//1`
4

Solution :Given `r_(1) = K [A]^(x) [B]^(y) … (i)`
On reducing the ORIGINAL volume to HALF , the concentration of reactants A and B will be doubled .
LET the new rate be `r_(2)` . Then , `r_(2) =k [2]^(x) [ 2 B] ^(y) or r_(2) = k xx 4 [A]^(x) [B]^(y) ""... (ii)`
or `r_(2) = 4 r_(1)`The rate will become four times relative to the initial rate .


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