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The rate of a gaseous reaction is halved when the volume of the vessel is doubled. What is the order of reaction ? |
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Answer» SOLUTION :Suppose, order of reaction is n and the reaction is A (G) `to`Products RATE=`k[A]^n`…(i) When volume is doubled, molar conc. becomes half and rate of reaction gets halved. `"Rate"/2=k(A/2)^n`…(ii) DIVIDING equation (i) by equation (ii), `(2)^1 =(2)^n` n=1 |
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