1.

The rate of a gaseous reaction triples when temperature is increased by 10^(@)C from 25^(@)C. The energy of activation of the reaction in kJ mol^(-1) will be

Answer»

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Solution :`"log"(3K)/(k)=(E_(a))/(2.303xx8.314 "JK mol"^(-1))XX(298K-283K)/(298Kxx283K)`
`:. log 3=(E_(a))/(19.15)xx(15)/(298 xx 283)`
`0.4771 =(E_(a)xx15)/(19.15xx298xx283)`
or `E_(a)=(0.4771xx19.15xx298xx283)/(15)`
`=513.68"kJ mol"^(-1)`.


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